
TrigonoMetri
Persamaan dlam fungsi tan
tan x = tan p, maka x= p + k. π
Penjelasan dengan langkah-langkah:
[tex]\sf \tan\ (x + \frac{1}{8}\pi) = \sqrt 3\ ; 0\leq x \leq 2\pi[/tex]
[tex]\sf \tan\ (x + \frac{1}{8}\pi) = \sqrt 3 = \tan \ (\frac{1}{3}\pi)[/tex]
[tex]\sf x + \frac{1}{8}\pi =\frac{1}{3}\pi + k.\pi[/tex]
[tex]\sf x = \frac{1}{3}\pi -\frac{1}{8}\pi + k.\pi[/tex]
[tex]\sf x = \frac{5}{24}\pi+ k.\pi[/tex]
[tex]\sf k= 0 , x = \frac{5}{24}\pi[/tex]
[tex]\sf k=1 , x = \frac{29}{24}\pi[/tex]
[tex]\sf k=2 , x = \frac{53}{24}\pi (tm\ krn \ > 2\pi)[/tex]
[tex]\sf untuk\ 0\leq x \leq 2\pi, \ HP \ x = \{\frac{5}{24}\pi , \ \frac{29}{24} \}[/tex]
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